Two coherent sources are `0.15` mm apart and fringes are observed 1m away with monochromatic light of wavelength `6000^(0)`. Find
The fringe width in a liquid of refraction index `5"/"2`.

Explanation

To solve the problem step by step, we will calculate the fringe width in a liquid with a given refractive index based on the information provided.

### Step 1: Understand the given data
- Distance between the two coherent sources (d) = 0.15 mm = \(0.15 \times 10^{-3}\) m = \(1.5 \times 10^{-4}\) m
- Distance from the sources to the screen (D) = 1 m
- Wavelength of the monochromatic light (λ) = 6000 Å = \(6000 \times 10^{-10}\) m = \(6 \times 10^{-7}\) m
- Refractive index of the liquid (μ) = \( \frac{5}{2} \)

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