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In an arrangement of double slit arrange...

In an arrangement of double slit arrangement fig. The slits are illuminated by light of wavelenth 600 mm. The distance of the first point on the screen from the centre maximum where intensity is 75% of central maximum is

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Let 1= distance between the slits
`V= (d1)/(dt)" path diff "x=(y1)/(D)" "(dx)/(dt)=(y)/(D)*(d1)/(dt)=(yv)/(D)`
Since a change in optical path difference of `lambda` corresponds to one fringe, so the number of fringes crossing point P per unit time is `(dx)/(dt)(1)/(lambda)= (yv)/(D)`.
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