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As shown in the figure Q, above point O ...

As shown in the figure Q, above point O is the position of first bright fringe. On the other side of O, D is the position of 11th bright fringe with respect to Q. If the wavelength of light used is `6000A^(0)` then the value of `S_(1)B` will be

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D will be 10th bright fringe with respect to 0 i.e., `n=10, lambda= 6000xx 10^(-10)m`
Path difference
`triangle x= S_(1)B= n lambda, " "triangle x = 10xx6xx10^(-7)= 6xx 10^(-6)m`.
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