Explanation

Suppose the two objects are a distance `triangle x` apart. Since these objects are almost at the focal length of the objective, the angle subtended by `triangle x`,
`i.e., triangle phi approx (triangle x)/(f_0)`
For the two objects to be clearly resolved, `triangle phi gt triangle theta`
(or) `(triangle x)/(f_0) gt (1.22 lambda)/(a) (triangle theta= (1.22 lambda)/(a))" (or) "triangle x gt (1.22 f_(0) lambda)/(a)`
(or) `triangle x gt ((1.22)(1xx 10^(-2)m)(6000xx 10^(-10)m))/((0.5xx 10^(-2)))= 1.46xx 10^(-6)m`
Because `10^(-6)m` is smaller than `1.46xx 10^(-6)m`, the two objects will not be resolved.