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When light of particular wavelength fall...

When light of particular wavelength falls on a plane surface at an angle of incidence `60^(@)` then the reflected light becomes completely plane polarized Find the refractive index of surface material and the angle of refraction through it.

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Angle of incident light with the surface is `30^(@)`. The angle of incidence `=90^(@)-30^(@)= 60^(@)`. Since reflected light is completely polarized, therefore incidence takes place polarizing angle of incidence `theta_p`.
`theta_(p)= 60^(@)`
Using Brewster.s law `mu = tan theta_(p)= tan 60^(@)" ", mu = sqrt(3)`.
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