The intensity of the polarized light transmitted through the analyzer is given by

Options

A. Brewster.s law
B. Malus law
C. Fresnel.s assumption
D. Law of superposition

Answer

To solve the question regarding the intensity of polarized light transmitted through an analyzer, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Polarization**:
- When unpolarized light passes through a polarizer, it becomes polarized. The intensity of the light after passing through the polarizer is reduced.

2. **Introducing the Analyzer**:
- After the light is polarized, it encounters another polarizing device known as the analyzer. The analyzer can be oriented at an angle (θ) relative to the axis of the polarizer.

3. **Applying Malus's Law**:
- Malus's Law states that the intensity (I) of polarized light transmitted through an analyzer is given by:
\[ I = I_0 \cos^2(\theta) \]
- Here, \(I_0\) is the intensity of the light after passing through the polarizer, and θ is the angle between the light's polarization direction and the axis of the analyzer.

4. **Conclusion**:
- Therefore, the intensity of the polarized light transmitted through the analyzer is governed by Malus's Law, which is the correct answer to the question.

### Final Answer:
The intensity of the polarized light transmitted through the analyzer is given by Malus's Law:
\[ I = I_0 \cos^2(\theta) \]