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The critical angles of three transparare...

The critical angles of three transpararent media K, L & M are `30^(@), 60^(@)" and "45^(@)` respectively. If `K_(P), L_(P)" and "M_(P)` are their polarising angles respectively, arrange them in increasing order

A

`K_(P), L_(P), M_(P)`

B

`M_(P), L_(P), K_(P)`

C

`L_(P), M_(P), K_(P)`

D

`K_(P), M_(P), L_(P)`

Text Solution

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The correct Answer is:
To solve the problem of arranging the polarizing angles of the three transparent media K, L, and M in increasing order, we will follow these steps: ### Step 1: Understand the relationship between critical angle and polarizing angle The polarizing angle \( P \) is related to the critical angle \( C \) by the formula: \[ \tan(P) = \frac{1}{\sin(C)} \] ### Step 2: Calculate the polarizing angle for medium K Given that the critical angle for medium K (\( C_K \)) is \( 30^\circ \): \[ \tan(P_K) = \frac{1}{\sin(30^\circ)} \] Since \( \sin(30^\circ) = \frac{1}{2} \): \[ \tan(P_K) = \frac{1}{\frac{1}{2}} = 2 \] Thus, \[ P_K = \tan^{-1}(2) \approx 63.43^\circ \] ### Step 3: Calculate the polarizing angle for medium L Given that the critical angle for medium L (\( C_L \)) is \( 60^\circ \): \[ \tan(P_L) = \frac{1}{\sin(60^\circ)} \] Since \( \sin(60^\circ) = \frac{\sqrt{3}}{2} \): \[ \tan(P_L) = \frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}} \] Thus, \[ P_L = \tan^{-1}\left(\frac{2}{\sqrt{3}}\right) \approx 49.1^\circ \] ### Step 4: Calculate the polarizing angle for medium M Given that the critical angle for medium M (\( C_M \)) is \( 45^\circ \): \[ \tan(P_M) = \frac{1}{\sin(45^\circ)} \] Since \( \sin(45^\circ) = \frac{1}{\sqrt{2}} \): \[ \tan(P_M) = \frac{1}{\frac{1}{\sqrt{2}}} = \sqrt{2} \] Thus, \[ P_M = \tan^{-1}(\sqrt{2}) \approx 54.73^\circ \] ### Step 5: Arrange the polarizing angles in increasing order Now we have: - \( P_K \approx 63.43^\circ \) - \( P_L \approx 49.1^\circ \) - \( P_M \approx 54.73^\circ \) Arranging these values in increasing order: 1. \( P_L \approx 49.1^\circ \) 2. \( P_M \approx 54.73^\circ \) 3. \( P_K \approx 63.43^\circ \) ### Final Answer The increasing order of the polarizing angles is: \[ P_L < P_M < P_K \]
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