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In Young.s double slit experiment the di...

In Young.s double slit experiment the distance between the sources is `7.7 mu""m`. If the wavelength of light used is 500 nanometre, the angular position of the third dark ringe from the centre fringe is

A

`10.9^(0)`

B

`0.15^(0)`

C

`11.3^(0)`

D

`9.4^(0)`

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To find the angular position of the third dark fringe in Young's double slit experiment, we can follow these steps: ### Step 1: Understand the parameters given - Distance between the slits (d) = 7.7 µm = \(7.7 \times 10^{-6}\) m - Wavelength of light (λ) = 500 nm = \(500 \times 10^{-9}\) m - We need to find the angular position of the third dark fringe, so n = 3. ### Step 2: Use the formula for dark fringes The angular position (θ) of the dark fringes in Young's double slit experiment can be calculated using the formula: \[ \theta = \sin^{-1}\left(\frac{(n + 0.5) \lambda}{d}\right) \] For the third dark fringe, we substitute n = 3. ### Step 3: Substitute the values into the formula Substituting the values into the formula gives: \[ \theta = \sin^{-1}\left(\frac{(3 + 0.5) \times 500 \times 10^{-9}}{7.7 \times 10^{-6}}\right) \] This simplifies to: \[ \theta = \sin^{-1}\left(\frac{3.5 \times 500 \times 10^{-9}}{7.7 \times 10^{-6}}\right) \] ### Step 4: Calculate the argument of the sine function Calculating the argument: \[ \theta = \sin^{-1}\left(\frac{1750 \times 10^{-9}}{7.7 \times 10^{-6}}\right) \] \[ \theta = \sin^{-1}\left(\frac{1750}{7.7} \times 10^{-3}\right) \] \[ \theta = \sin^{-1}(0.22727) \] ### Step 5: Calculate the angle in radians Using a calculator, we find: \[ \theta \approx 0.2309 \text{ radians} \] ### Step 6: Convert radians to degrees To convert radians to degrees, we use the conversion factor \( \frac{180}{\pi} \): \[ \theta_{degrees} = 0.2309 \times \frac{180}{\pi} \approx 13.23 \text{ degrees} \] ### Step 7: Conclusion The angular position of the third dark fringe from the center fringe is approximately **13.23 degrees**.
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AAKASH SERIES-WAVES OPTICS-EXERCISE -III (DOPPLER EFFECT IN LIGHT, INTERFERENCE)
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