Home
Class 12
PHYSICS
Find the maximum magnifying power of a c...

Find the maximum magnifying power of a compound microscope having a 25 diopter lens as the objective, a 5 diopter lens as the eyepiece and the separation 30 cm between the two lenses. The least distance for clear vision is 25 cm.

A

`250`

B

`400`

C

`220`

D

`100`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • WAVES OPTICS

    AAKASH SERIES|Exercise EXERCISE -III (POLARISITION)|10 Videos

  • WAVES OPTICS

    AAKASH SERIES|Exercise EXERCISE -III (DOPPLER EFFECT IN LIGHT, INTERFERENCE)|25 Videos

  • WAVES

    AAKASH SERIES|Exercise EXERCISE-III (Doppler effect :)|15 Videos

Similar Questions

Explore conceptually related problems

An object is to be seen through a simple microscope of focal length 12 cm. Where should the object be placed so as to produce maximum angular magnification? The least distance for clear vision is 25 cm.

The magnifying power of a simple microscope is 6. The focal length of its lens in metres will be, if least distance of distinct vision is 25cm

The focal lengths of the objective and the eyepiece of an astronomical telescope are 20 cm and 5 cm respectively. If the final image is formed at a distance of 30 cm from the eye piece, find the separation between the lenses for distinct vision:

The magnifying power of a telescope is 9. When it is adjusted for parallel rays the distance between the objective and eyepiece is 20cm . The focal lengths of lenses are

In a compound microscope, the object is 1 cm from the objective lens. The lenses are 30 cm apart and the intermediate image is 5 cm from the eye-piece. What magnification is produced?

The maximum magnification that can be obtained with a convex lens of focal length 2.5 cm is (the least distance of distinct vision is 25 cm )

The separation between the objective and the eyepiece of a compound microscope can be adjusted between 9.8 cm to 11.8 cm. If the focal lengths of the objective and the eyepiece are 1.0 cm and 6 cm respectively, find the range of the magnifying power if the image is always needed at 24 cm from the eye.

(a) Draw a labelled ray diagram showing the formation of a final image by a compound microscope at least distance of distinct vision. (b) The total magnification produced by a compound microscope is 20. The magnification produced by the piece is 5. The microscope is focused on a certain object. The distance between the objective and eyepiece is observed to be 14cm. If least distance of distinct vision is 20cm, calculate the focal length of the objective and the eye piece.

The figure shows a simple arrangement which works as an astronomical telescope. The arrangement consists of two convex lenses placed coaxially. The lens which faces a distant object is called the objective. It has a large aperture and a large focal length also. The second lens is closed to the observers eyes. It is called the eyepiece. It has a smaller aperture as compared to the objective. Its focal length is also small in comparison to objective. The objective forms a real image of a distant object. This image acts as the object for the eyepiece. The eye-piece may form its image at a large distance (oo) or at least distance of distinct vision (D = 25 cm). The magnifying power of the telescope is the ratio (-beta)/(alpha) . Maximum angular magnification is produced when the final image is at the least distance of distinct vision. A telescope has an objective of focal length 50 cm and an eye-piece of focal length 5 cm. The least distance of distinct vision is 25 cm. The telescope is adjusted for distinct vision and it is focussed on an object 200 cm away. The length of the telescope is

The length of the compound microscope is 14 cm. The magnifying power for relaxed eye is 25 . If the focal length of eye lens is 5 cm , then the object distance for objective lens will be