A metal rod of resistance `20Omega` is fixed along diameter of a conducting ring of radius 0.1m and on x-y plane. There is a magnetic field B=(50t) . The ring roatates with an angular velocity `omega=20rad//s` about its axis. An external resistance resistance `10Omega` is connected cross the centre of the ring an rim. The current through external resistance is

Explanation

The equivalent circuit is
`e=(1)/(2)Bl^(2) omega =(1)/(2) xx 50 xx 0.1 xx 0.1 xx 20`,
`:.` e = 5 V
Hence the current through the external resistance is
`i=(e)/(R)" ":. i=(5)/(15)=(1)/(3)` amp