The loop ABCD is moving with velocity v towards right. The magnetic field is 4 T. The loop is connected to a resistance of `8Omega`. If steady current of 2 A flows in the loop, then value of v, if loop has resistance of `4Omega`, is (Given, AB = 30 cm, `sin 37^(@)=(3)/(5)`)

Explanation

The induced emf in the loop is e = Blv `e=B(AD) sin 37^(@) v = 4 xx 0.3 sin 37^(@)v`
Effective resistance of the circuit is R = (4+8) = 12 ohm
Hence `i=(e)/(R)=(Blv) implies 2=(4xx0.3xx sin37^(@) mu)/((4+8))`
`:. v=(100)/(3) m//s`