Find the force experienced by a chloride ion having 4 electrons removed, when placed in an electric field of intensity `2NC^(-1)`.

Explanation

To find the force experienced by a chloride ion with 4 electrons removed when placed in an electric field of intensity \(2 \, \text{N/C}\), we can follow these steps:

### Step 1: Determine the charge of the chloride ion
Since the chloride ion has 4 electrons removed, it has a positive charge equal to the charge of 4 electrons. The charge of a single electron is approximately \(1.6 \times 10^{-19} \, \text{C}\).

\[ \text{Charge of chloride ion} = 4 \times \text{Charge of one electron} = 4 \times 1.6 \times 10^{-19} \, \text{C} \]
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