The surface charge density of a thin charged disc of radius R is `sigma`. The value of the electric field at the centre of the disc `(sigma)/(2 in_(0))`. With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc is

Options

A. A. reduced by 70.7%
B. B. reduced by 29.3%
C. C. reduced by 9.7 %
D. D. reduced by 14.6%

Explanation

To solve the problem, we need to find the electric field along the axis of a charged disc at a distance \( R \) from its center, given that the surface charge density is \( \sigma \) and the electric field at the center of the disc is \( \frac{\sigma}{2 \epsilon_0} \).

### Step-by-Step Solution:

1. **Understand the Electric Field at the Center**:
The electric field \( E \) at the center of the disc is given as:
\[
E_{\text{center}} = \frac{\sigma}{2 \epsilon_0}
...