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The electrostatic force between protons ...

The electrostatic force between protons is how many times stronger than gravitational force.

A

`10^(34)`

B

`10^(35)`

C

`10^(36)`

D

`10^(37)`

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The correct Answer is:
To find how many times stronger the electrostatic force between protons is compared to the gravitational force, we can follow these steps: ### Step 1: Write the formulas for electrostatic and gravitational forces. The electrostatic force \( F_e \) between two protons can be expressed using Coulomb's law: \[ F_e = k \frac{q^2}{r^2} \] where: - \( k \) is Coulomb's constant (\( 9 \times 10^9 \, \text{N m}^2/\text{C}^2 \)), - \( q \) is the charge of a proton (\( 1.6 \times 10^{-19} \, \text{C} \)), - \( r \) is the distance between the protons. The gravitational force \( F_g \) between two protons can be expressed using Newton's law of gravitation: \[ F_g = G \frac{m^2}{r^2} \] where: - \( G \) is the gravitational constant (\( 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \)), - \( m \) is the mass of a proton (\( 1.67 \times 10^{-27} \, \text{kg} \)). ### Step 2: Set up the ratio of the forces. To find how many times stronger the electrostatic force is compared to the gravitational force, we take the ratio: \[ \frac{F_e}{F_g} = \frac{k \frac{q^2}{r^2}}{G \frac{m^2}{r^2}} = \frac{k \cdot q^2}{G \cdot m^2} \] Notice that the \( r^2 \) terms cancel out. ### Step 3: Substitute the known values. Now we substitute the known values into the equation: \[ \frac{F_e}{F_g} = \frac{9 \times 10^9 \cdot (1.6 \times 10^{-19})^2}{6.67 \times 10^{-11} \cdot (1.67 \times 10^{-27})^2} \] ### Step 4: Calculate the numerator and denominator. First, calculate the numerator: \[ 9 \times 10^9 \cdot (1.6 \times 10^{-19})^2 = 9 \times 10^9 \cdot 2.56 \times 10^{-38} = 23.04 \times 10^{-29} \] Now calculate the denominator: \[ 6.67 \times 10^{-11} \cdot (1.67 \times 10^{-27})^2 = 6.67 \times 10^{-11} \cdot 2.7889 \times 10^{-54} = 18.60 \times 10^{-65} \] ### Step 5: Divide the results. Now divide the results from the numerator and denominator: \[ \frac{F_e}{F_g} = \frac{23.04 \times 10^{-29}}{18.60 \times 10^{-65}} = 1.238 \times 10^{36} \] ### Step 6: Conclusion. Thus, the electrostatic force between two protons is approximately \( 10^{36} \) times stronger than the gravitational force between them. ### Summary of the solution: The electrostatic force between protons is \( 10^{36} \) times stronger than the gravitational force. ---
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