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If E is the electric field intensity of ...

If E is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to

A

E

B

`E^(2)`

C

`1//E^(2)`

D

`E^(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the relationship between electric field intensity (E) and electrostatic energy density, we can follow these steps: ### Step 1: Understand the concept of electrostatic energy density Electrostatic energy density (u) is defined as the energy stored per unit volume in an electric field. ### Step 2: Recall the formula for electrostatic energy density The formula for electrostatic energy density is given by: \[ u = \frac{1}{2} \epsilon_0 E^2 \] where: - \( u \) is the energy density, - \( \epsilon_0 \) is the permittivity of free space (a constant), - \( E \) is the electric field intensity. ### Step 3: Analyze the formula From the formula \( u = \frac{1}{2} \epsilon_0 E^2 \), we can see that the energy density \( u \) is directly proportional to the square of the electric field intensity \( E \). ### Step 4: Determine the proportionality Since \( \epsilon_0 \) is a constant, we can conclude that: \[ u \propto E^2 \] ### Conclusion Thus, the electrostatic energy density is proportional to the square of the electric field intensity. Therefore, the correct answer is: \[ \text{Electrostatic energy density is proportional to } E^2. \]
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