In 1 gram of solid, there are `5 xx 10^(21)` atoms. If one electron is removed from every one of 0.1% of atoms of the solid, the charge gained by the solid is

Options

A. `+0.018C`
B. `+0.8C`
C. `+8 mu C`
D. `-0.08C`

Answer

To solve the problem, we need to calculate the total charge gained by the solid when one electron is removed from 0.1% of its atoms. Here’s a step-by-step solution:

### Step 1: Determine the total number of atoms in the solid.
Given that there are \(5 \times 10^{21}\) atoms in 1 gram of the solid.

### Step 2: Calculate the number of atoms from which electrons are removed.
We need to find 0.1% of the total number of atoms:
\[ \text{Number of atoms from which electrons are removed} = 0.1\% \text{ of } 5 \times 10^{21} \]
\[ = \frac{0.1}{100} \times 5 \times 10^{21} = 5 \times 10^{21} \times 0.001 = 5 \times 10^{18} \text{ atoms} \]

### Step 3: Calculate the total number of electrons removed.
Since one electron is removed from each of these atoms, the total number of electrons removed is:
\[ n = 5 \times 10^{18} \text{ electrons} \]

### Step 4: Calculate the total charge removed.
The charge of one electron is approximately \(1.6 \times 10^{-19}\) coulombs. Therefore, the total charge \(q\) removed is:
\[ q = n \times e = 5 \times 10^{18} \times 1.6 \times 10^{-19} \]
\[ = 8 \times 10^{-1} \text{ coulombs} = 0.8 \text{ coulombs} \]

### Step 5: Determine the charge gained by the solid.
Since electrons are negatively charged, removing them results in a positive charge for the solid. Thus, the charge gained by the solid is:
\[ \text{Charge gained by the solid} = +0.8 \text{ coulombs} \]

### Final Answer:
The charge gained by the solid is \(+0.8 \text{ C}\).

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