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The displacement bar(r ) of a charge Q i...

The displacement `bar(r )` of a charge Q in an electric field `E= e_(1) hat(i) + e_(2) hat(j) + e_(3) hat(k) " is " bar(r )= a hat(i) + b hat(j)`. The work done is

A

`Q(a e_(1) + b e_(2))`

B

`Q sqrt((a e_(1))^(2) + (b e_(2))^(2))`

C

`Q (e_(1) + e_(2)) sqrt(a^(2) + b^(2))`

D

`(e_(1)^(2) + e_(2)^(2)) (a + b)`

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AI Generated Solution

The correct Answer is:
To find the work done \( W \) when a charge \( Q \) is displaced in an electric field \( \mathbf{E} \), we can follow these steps: ### Step 1: Understand the formula for work done The work done \( W \) by an electric field when a charge is moved is given by the formula: \[ W = \mathbf{F} \cdot \mathbf{d} \] where \( \mathbf{F} \) is the force acting on the charge and \( \mathbf{d} \) is the displacement vector. ### Step 2: Calculate the force on the charge The force \( \mathbf{F} \) acting on the charge \( Q \) in an electric field \( \mathbf{E} \) is given by: \[ \mathbf{F} = Q \mathbf{E} \] Given that the electric field \( \mathbf{E} = e_1 \hat{i} + e_2 \hat{j} + e_3 \hat{k} \), we can express the force as: \[ \mathbf{F} = Q (e_1 \hat{i} + e_2 \hat{j} + e_3 \hat{k}) \] ### Step 3: Write the displacement vector The displacement vector \( \mathbf{d} \) is given as: \[ \mathbf{d} = a \hat{i} + b \hat{j} \] ### Step 4: Substitute the values into the work done formula Now substituting \( \mathbf{F} \) and \( \mathbf{d} \) into the work done formula: \[ W = \mathbf{F} \cdot \mathbf{d} = (Q (e_1 \hat{i} + e_2 \hat{j} + e_3 \hat{k})) \cdot (a \hat{i} + b \hat{j}) \] ### Step 5: Calculate the dot product Now, we calculate the dot product: \[ W = Q \left( (e_1 \hat{i} + e_2 \hat{j} + e_3 \hat{k}) \cdot (a \hat{i} + b \hat{j}) \right) \] Using the properties of the dot product: \[ W = Q \left( e_1 a + e_2 b + e_3 \cdot 0 \right) \] Since \( \hat{k} \) is orthogonal to both \( \hat{i} \) and \( \hat{j} \), the term involving \( e_3 \) becomes zero. ### Step 6: Final expression for work done Thus, the work done is: \[ W = Q (e_1 a + e_2 b) \] ### Final Answer The work done \( W \) is given by: \[ W = Q (e_1 a + e_2 b) \]
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