The work function of a metal is 3.0 V. It is illuminated by a light of wave length `3xx10^(-7)m`. Calculate i) threshold frequency, ii) the maximum energy of photoelectrons, iii) the stopping potential.
`(h=6.63xx10^(-34)Js and c=3xx10^(8)ms^(-))`.

Explanation

To solve the problem step by step, we will calculate the threshold frequency, the maximum energy of photoelectrons, and the stopping potential based on the given data.

### Given Data:
- Work function of the metal, \( \phi = 3.0 \, \text{eV} \)
- Wavelength of the light, \( \lambda = 3 \times 10^{-7} \, \text{m} \)
- Planck's constant, \( h = 6.63 \times 10^{-34} \, \text{Js} \)
- Speed of light, \( c = 3 \times 10^{8} \, \text{ms}^{-1} \)
- Conversion factor: \( 1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J} \)
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