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The slope of the graph drawn between sto...

The slope of the graph drawn between stopping potential and frequency of incident radiation will be

A

`(h)/(c )`

B

he

C

`eh^(2)`

D

`e^(2)h`

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The correct Answer is:
To find the slope of the graph drawn between stopping potential (V₀) and frequency (ν) of incident radiation, we can follow these steps: ### Step 1: Understand the Photoelectric Effect In the photoelectric effect, when light of frequency ν strikes a metal surface, it imparts energy to electrons. The energy of the incident radiation can be expressed using Planck's equation: \[ E = hν \] where \( E \) is the energy of the photon, \( h \) is Planck's constant, and \( ν \) is the frequency of the incident radiation. ### Step 2: Relate Stopping Potential to Energy The stopping potential (V₀) is the potential needed to stop the most energetic photoelectrons emitted from the surface. The kinetic energy (KE) of the emitted electrons can be expressed as: \[ KE = eV₀ \] where \( e \) is the charge of the electron. ### Step 3: Set Up the Energy Equation According to the conservation of energy, the energy of the incident photon is used to overcome the work function (φ) of the metal and provide kinetic energy to the emitted electrons: \[ hν = φ + eV₀ \] ### Step 4: Rearranging the Equation Rearranging the equation gives us: \[ eV₀ = hν - φ \] This can be rewritten as: \[ V₀ = \frac{h}{e}ν - \frac{φ}{e} \] ### Step 5: Identify the Slope From the equation \( V₀ = \frac{h}{e}ν - \frac{φ}{e} \), we can see that this is in the form of a linear equation \( y = mx + c \), where: - \( y \) is the stopping potential \( V₀ \) - \( x \) is the frequency \( ν \) - \( m \) (the slope) is \( \frac{h}{e} \) ### Conclusion Thus, the slope of the graph drawn between stopping potential (V₀) and frequency (ν) of incident radiation is: \[ \text{Slope} = \frac{h}{e} \] ---
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AAKASH SERIES-DUAL NATURE OF RADIATION AND MATTER-EXERCISE-I
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