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The ratio of velocities of a proton and ...

The ratio of velocities of a proton and an `alpha` particle is 4 : 1. The ratio of their De Broglie wave lengths will be

A

`4:1`

B

`1:4`

C

`1:2`

D

`1:1`

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The correct Answer is:
To solve the problem, we need to find the ratio of the De Broglie wavelengths of a proton and an alpha particle given the ratio of their velocities. ### Step-by-Step Solution: 1. **Understand the De Broglie Wavelength Formula**: The De Broglie wavelength (λ) is given by the formula: \[ \lambda = \frac{h}{mv} \] where \( h \) is Planck's constant, \( m \) is the mass of the particle, and \( v \) is its velocity. 2. **Write the Expressions for the Wavelengths**: For a proton (p) and an alpha particle (α), the De Broglie wavelengths can be expressed as: \[ \lambda_p = \frac{h}{m_p v_p} \] \[ \lambda_\alpha = \frac{h}{m_\alpha v_\alpha} \] 3. **Find the Ratio of the Wavelengths**: To find the ratio of the wavelengths, we divide the wavelength of the proton by the wavelength of the alpha particle: \[ \frac{\lambda_p}{\lambda_\alpha} = \frac{\frac{h}{m_p v_p}}{\frac{h}{m_\alpha v_\alpha}} = \frac{m_\alpha v_\alpha}{m_p v_p} \] Here, \( h \) cancels out. 4. **Substitute the Known Mass and Velocity Ratios**: We know from the problem that: - The mass of an alpha particle \( m_\alpha \) is approximately 4 times the mass of a proton \( m_p \): \[ m_\alpha = 4m_p \] - The ratio of the velocities is given as \( v_p : v_\alpha = 4 : 1 \), which means: \[ \frac{v_p}{v_\alpha} = 4 \quad \Rightarrow \quad \frac{v_\alpha}{v_p} = \frac{1}{4} \] 5. **Plug in the Ratios**: Now, substituting these ratios into the wavelength ratio: \[ \frac{\lambda_p}{\lambda_\alpha} = \frac{(4m_p)(\frac{1}{4}v_p)}{m_p v_p} \] Simplifying this gives: \[ \frac{\lambda_p}{\lambda_\alpha} = \frac{4m_p \cdot \frac{1}{4}v_p}{m_p v_p} = \frac{4 \cdot \frac{1}{4}}{1} = 1 \] 6. **Conclusion**: Therefore, the ratio of the De Broglie wavelengths of the proton and the alpha particle is: \[ \lambda_p : \lambda_\alpha = 1 : 1 \] ### Final Answer: The ratio of their De Broglie wavelengths is \( 1 : 1 \).
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