Home
Class 12
PHYSICS
The photo electric threshold wavelength ...

The photo electric threshold wavelength for a metal is `2750A^(@)`, The minimum energy of a photon that can produce photoelectric effect in the metal is

A

0.045eV

B

0.45 eV

C

4.5 eV

D

0.0045 eV

Text Solution

AI Generated Solution

The correct Answer is:
To find the minimum energy of a photon that can produce the photoelectric effect in a metal with a threshold wavelength of 2750 Å, we can use the relationship between energy, wavelength, and Planck's constant. Here’s a step-by-step solution: ### Step 1: Understand the relationship between energy and wavelength The energy \( E \) of a photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] where: - \( E \) is the energy of the photon, - \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{Js} \)), - \( c \) is the speed of light (\( 3.00 \times 10^8 \, \text{m/s} \)), - \( \lambda \) is the wavelength of the photon. ### Step 2: Convert the wavelength from Angstroms to meters The given threshold wavelength is \( 2750 \, \text{Å} \). We need to convert this to meters: \[ \lambda = 2750 \, \text{Å} = 2750 \times 10^{-10} \, \text{m} = 2.75 \times 10^{-7} \, \text{m} \] ### Step 3: Substitute the values into the energy formula Now we can substitute the values of \( h \), \( c \), and \( \lambda \) into the energy formula: \[ E = \frac{(6.626 \times 10^{-34} \, \text{Js})(3.00 \times 10^8 \, \text{m/s})}{2.75 \times 10^{-7} \, \text{m}} \] ### Step 4: Calculate the energy Calculating the numerator: \[ hc = 6.626 \times 10^{-34} \times 3.00 \times 10^8 = 1.9878 \times 10^{-25} \, \text{Jm} \] Now, divide by the wavelength: \[ E = \frac{1.9878 \times 10^{-25}}{2.75 \times 10^{-7}} \approx 7.23 \times 10^{-19} \, \text{J} \] ### Step 5: Convert energy from Joules to electron volts To convert Joules to electron volts, we use the conversion factor \( 1 \, \text{eV} = 1.602 \times 10^{-19} \, \text{J} \): \[ E \approx \frac{7.23 \times 10^{-19}}{1.602 \times 10^{-19}} \approx 4.51 \, \text{eV} \] ### Final Answer Thus, the minimum energy of a photon that can produce the photoelectric effect in the metal is approximately: \[ E \approx 4.5 \, \text{eV} \]
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE OF RADIATION AND MATTER

    AAKASH SERIES|Exercise EXERCISE=II|42 Videos
  • CURRENT ELECTRICITY

    AAKASH SERIES|Exercise EXERCISE - IA|2 Videos
  • ELECTRIC CHARGES AND FIELDS

    AAKASH SERIES|Exercise Practice Exercise|57 Videos

Similar Questions

Explore conceptually related problems

Find the maximum wavelength of light that can cause photoelectric effect in lithium.

The photoelectric threshold wavelength of a metal is 300 nm. The maximum kinetic energy of electrons ejected from the metal surface by ultraviolet light of wavelength 250 nm is nearly (given h = 4.14*10^-15 eV s and c= 3*10^8 ms^-1)

The threshold wavelength for ejection of electrons from a metal is 250 nm. The work function for the photoelectric emission from the metal is

The threshold wavelength for ejection of electrons from a metal is 430 nm. The work function for the photoelectric emission from the metal is

The threshold wavelength for ejection of electrons from a metal is 330 nm. The work function for the photoelectric emission from the metal is

The threshold wavelength for ejection of electrons from a metal is 450 nm. The work function for the photoelectric emission from the metal is

The threshold wavelength for ejection of electrons from a metal is 280 nm. The work function for the photoelectric emission from the metal is

The threshold wavelength for ejection of electrons from a metal is 230 nm. The work function for the photoelectric emission from the metal is

The threshold wavelength for ejection of electrons from a metal is 350 nm. The work function for the photoelectric emission from the metal is

The threshold wavelength for ejection of electrons from a metal is 650 nm. The work function for the photoelectric emission from the metal is

AAKASH SERIES-DUAL NATURE OF RADIATION AND MATTER-PRACTICE EXERCISEX
  1. The maximum kinetic energy of an electron is E when the incident wavel...

    Text Solution

    |

  2. Two sources A and B have same power . The wavelength of radiation of A...

    Text Solution

    |

  3. The photo electric threshold wavelength for a metal is 2750A^(@), The ...

    Text Solution

    |

  4. When the incident wavelengths are lamda and lamda//2 the kinetic energ...

    Text Solution

    |

  5. A 1 kw radio transmitter operates at a frequency of 880 KHz how many p...

    Text Solution

    |

  6. The threshold wavelength for photo electric emission from a material i...

    Text Solution

    |

  7. Light of wavelength 4000A∘ is incident on a metal surface. The maximum...

    Text Solution

    |

  8. Monochromatic light incident on a metal surface emits electrons with k...

    Text Solution

    |

  9. Three metals have work functions in the ratio 2 3:4. Graphs are drawn ...

    Text Solution

    |

  10. Two photons of energies twice and thrice the work function of a metal ...

    Text Solution

    |

  11. The work function of substance is 4.0 eV. The longest wavelength of li...

    Text Solution

    |

  12. Photoelectric work function of a metal is 1eV, light of wavelength lam...

    Text Solution

    |

  13. When a monochromatic point source of light is at a distance of 0.2 m...

    Text Solution

    |

  14. The work function of a substance is 12.4 eV. The longest wavelength of...

    Text Solution

    |

  15. A surface irradiated with light of wavelength 480 nm gives out electro...

    Text Solution

    |

  16. What P.D. must be applied to stop the fastest photo electron emitted b...

    Text Solution

    |

  17. The threshold frequency for photo electric effect for a metal surface ...

    Text Solution

    |

  18. The work functions of metals A and B are in the ratio 1 : 2. If light ...

    Text Solution

    |

  19. When a metal surface is illuminated by light of wavelengths 400 nm and...

    Text Solution

    |

  20. V(1) and V(2) are the stopping potentials for the incident radiations ...

    Text Solution

    |