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Light of wavelength 4000A∘ is incident o...

Light of wavelength 4000A∘ is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface?

A

1 eV

B

2.1 V

C

4000 V

D

3.1 V

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The correct Answer is:
To find the work function of the metal surface when light of wavelength 4000 Å is incident on it, we can use the photoelectric equation derived from Einstein's photoelectric effect theory. The equation is given by: \[ K_{max} = E - \phi \] Where: - \( K_{max} \) is the maximum kinetic energy of the emitted photoelectron. - \( E \) is the energy of the incident light. - \( \phi \) is the work function of the metal. ### Step-by-Step Solution: **Step 1: Convert the wavelength from Ångströms to meters.** Given: \[ \text{Wavelength} (\lambda) = 4000 \, \text{Å} = 4000 \times 10^{-10} \, \text{m} \] **Step 2: Calculate the energy of the incident light using the formula:** \[ E = \frac{hc}{\lambda} \] Where: - \( h \) (Planck's constant) = \( 6.626 \times 10^{-34} \, \text{J s} \) - \( c \) (speed of light) = \( 3 \times 10^{8} \, \text{m/s} \) Substituting the values: \[ E = \frac{(6.626 \times 10^{-34}) \times (3 \times 10^{8})}{4000 \times 10^{-10}} \] Calculating: \[ E = \frac{1.9878 \times 10^{-25}}{4 \times 10^{-7}} = 4.9695 \times 10^{-19} \, \text{J} \] **Step 3: Convert the energy from joules to electron volts.** Using the conversion factor \( 1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J} \): \[ E = \frac{4.9695 \times 10^{-19}}{1.6 \times 10^{-19}} \approx 3.1059 \, \text{eV} \] **Step 4: Use the photoelectric equation to find the work function.** Given: \[ K_{max} = 2 \, \text{eV} \] Substituting into the equation: \[ K_{max} = E - \phi \] \[ 2 = 3.1059 - \phi \] Rearranging gives: \[ \phi = 3.1059 - 2 \] \[ \phi \approx 1.1059 \, \text{eV} \] **Step 5: Round the work function to a reasonable value.** Since we are looking for a simple numerical answer, we can round: \[ \phi \approx 1 \, \text{eV} \] ### Final Answer: The work function of the metal surface is approximately **1 eV**. ---
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