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For scattering by an .inverse square. fi...

For scattering by an .inverse square. field (such as that produced by a charged nucleus in Rutherford.s model), the relation between impact parameter b and the scattering angle `theta` is given by,
`b=(Ze^(2)cot theta//2)/(4pi epsilon_(0)((1)/(2)mv^(2)))`
Why is it that the mass of the nucleus does not enter the formula above but its charge does ?

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To understand why the mass of the nucleus does not enter the formula for the impact parameter \( b \) in scattering by an inverse square field, we can analyze the situation step by step. ### Step-by-Step Solution: 1. **Understanding the Formula**: The formula given is: \[ b = \frac{Ze^2 \cot(\theta/2)}{4\pi \epsilon_0 \left(\frac{1}{2}mv^2\right)} ...
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