A 10 kg satellite circles earth once every 2h in an orbit having a radius of 8000km. Assuming that Bohr's angular momentum postulate applies to a satellite just as it does to an electron in the hydrogen atom, then the quantum number of the orbit of satellite is

Explanation

`mv_(n)r_(n)=nh//2pi`
Here m = 10 kg and `r_(n)=8xx10^(6)m`. We have the time period T of the circling satellite as 2h. That is T = 7200 s.
Thus the velocity `v_(n)=2pi r_(n)//T`.
The quantum number of the orbit of satellite
`n=(2pi xx 8xx10^(6)m)^(2)xx10//(7200sxx6.64xx10^(-34)JS)`
`=5.3xx10^(45)`
Note that the quantum number for the satellite motion is extremely large ! In fact for such large quantum numbers the results of quantization condition tend to those of classical physics.