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An alpha nucleus of energy (1)/(2)mv^(2)...

An alpha nucleus of energy `(1)/(2)mv^(2)` bomobards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to

A

`(1)/(vartheta)`

B

`(1)/(Ze)`

C

`vartheta^(2)`

D

`(1)/(m)`

Text Solution

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The correct Answer is:
D
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AAKASH SERIES-ATOMS-EXERCISE - II
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  10. Electrons from n = 2 to n= 1 in hydrogen atom is made to fall on a met...

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