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If a hydrogen atom emit a photon of ener...

If a hydrogen atom emit a photon of energy `12.1 eV` , its orbital angular momentum changes by `Delta` L. then `Delta` L equals

A

`1.05xx10^(-34)` Js

B

`2.11xx10^(-34)` Js

C

`3.16xx10^(-34)` Js

D

`4.22xx10^(-34)` Js

Text Solution

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The correct Answer is:
B
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