The binding energy per nucleon of deuteron `(._(1)^(2)H)` and helium nucleus `(._(2)^(4)He)` is `1.1 MeV` and `7 MeV` respectively. If two deutron nuclei react to form a single helium nucleus, then the energy released is-

Explanation

The fusion reaction is `2(._1H^2) to ._2He^4 +Q`
Q=Total binding energy of the product `._2He^4` -Total binding energy of reactant i.e., two deuterons.
=4 x 7.0 - 4 x 1.1 = 28.0 -4.4 =23.6 MeV