Four vessels A,B,C and D contain respectively 20g atom (`T_(1//2)` = 5h) 2g atom (`T_(1//2)`=1h) 5g atom (`T_(1//2)` = 2h) and 10g atom (`T_(1//2)` = 3h) of different radio nuclides in the 12 beginning, the maximum activity would be exhibited by the vessel is

Explanation

To determine which vessel exhibits the maximum activity, we need to calculate the activity for each vessel using the formula for radioactive decay. The activity \( A \) is given by the formula:

\[ A = n \cdot \lambda \]

where:
- \( n \) is the number of atoms (which is proportional to the mass of the substance),
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