How much `U^(235)` is consumed in a day in an atomic power house operating at 400 MW, provided the whole of the mass of `U^(235)` is converted into energy?

Explanation

power = 400 MW= `400xx10^6` W , time = 1 day = 86,400 s.
Energy produced , E= power x time
`=400xx10^6xx86,400=3.456xx10^13` J
As the whole of mass is converted into energy , by Einstein.s mass-energy
`E=Mc^2`
`M=E/c^2=(3.456xx10^13)/(3xx10^8)^2=3.84xx10^(-4)` kg =0.384 g.