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A gamma ray photon of energy 1896 MeV an...

A gamma ray photon of energy 1896 MeV annihilates to produce a proton-antiproton pair. If the rest mass of each of the particles involved be 1.007276 a.m.u approximately, find how much K.E these will carry?

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To solve the problem, we need to find the kinetic energy (K.E) carried by the proton and antiproton produced from the annihilation of a gamma ray photon with energy 1896 MeV. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Energy of the gamma photon, \( E_{\gamma} = 1896 \, \text{MeV} \) - Rest mass of proton (and antiproton), \( m_0 = 1.007276 \, \text{a.m.u} \) ...
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AAKASH SERIES-NUCLEI-Practice Exercise
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