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A hydrogen like atom of atomic number Z ...

A hydrogen like atom of atomic number Z is in and excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. If it makes a transition to quantum state n, photon of energy 40.8 eV is emitted. Find n , Z and the gound state energy (in eV) for this atom, Also calculate the minimum energy (in eV) that can be emitted by this atom during de-exitation, Ground state energy of hydrogen atom is `13. 6 eV`

A

prompt nevtrons

B

delayed neutrons

C

slowed prompt neutrons

D

2 or 3

Text Solution

Verified by Experts

The correct Answer is:
D
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