Home
Class 12
PHYSICS
A nucleus with Z =92 emits the following...

A nucleus with Z =92 emits the following in a sequence:
`alpha,beta^(-),beta^(-),alpha,alpha,alpha,alpha,alpha,beta^(-),beta^(-),alpha,beta^(+),beta^(+),alpha`. The Z of the resulting nucleus is

A

76

B

78

C

82

D

74

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    AAKASH SERIES|Exercise Exercise-II|40 Videos

  • NUCLEI

    AAKASH SERIES|Exercise Practice Exercise|40 Videos

  • NUCLEI

    AAKASH SERIES|Exercise Practice Exercise|40 Videos

  • NUCLEAR PHYSICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE PRACTICE SHEET (ADVANCED) Integer Type Questions|3 Videos

  • OPTICAL INSTRUMENTS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE -I) (OPTICAL INSTRUMENTS) (LEVEL-I (MAIN)) (SUBJECTIVE OBJECTIVE TYPE QUESTIONS)|21 Videos

Similar Questions

Explore conceptually related problems

If f(alpha,beta)=|(cos alpha,-sin alpha,1),(sin alpha,cos alpha,1),(cos(alpha+beta),-sin(alpha+beta),1)|, then

Evaluate the following: |[1,1,1],[alpha, beta, gamma],[beta gamma, gamma alpha, alpha beta]|

If alpha, beta, gamma are the cube roots of 8 , then |(alpha,beta,gamma),(beta,gamma,alpha),(gamma,alpha,beta)|=

If A(alpha, beta)=[("cos" alpha,sin alpha,0),(-sin alpha,cos alpha,0),(0,0,e^(beta))] , then A(alpha, beta)^(-1) is equal to

Factorise alpha^2 +beta^2 + alpha beta

Sum the series tan alpha tan (alpha+beta)+tan(alpha+beta)+tan(alpha+2beta)+tan(alpha+2beta)tan(alpha+3beta)+… to n terms

(sinalpha+sinbeta-sin(alpha+beta))/(sinalpha+sinbeta+sin(alpha+beta))=tan(alpha/2)tan(beta/2)

alpha + beta = 5 , alpha beta= 6 .find alpha - beta

If A=[{:(a,b),(b,a):}] and A^(2)=[{:(alpha, beta),(beta, alpha):}] then

f(alpha,beta) = cos^2(alpha)+ cos^2(alpha+beta)- 2 cosalpha cosbeta cos(alpha+beta) is