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The distance of closest approach of an a...

The distance of closest approach of an `alpha`-particle fired at nucleus with momentum p is d. The distance of closest approach when the `alpha`-particle is fired at same nucleus with momentum 3p will be

A

`2r_0`

B

`4r_0`

C

`r_0/2`

D

`r_0/4`

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The correct Answer is:
D
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