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As a charged particle 'q' moving with a ...

As a charged particle 'q' moving with a velocity `vec(v)` enters a uniform magnetic field `vec(B)`, it experience a force `vec(F) = q(vec(v) xx vec(B)). For theta = 0^(@) or 180^(@), theta` being the angle between `vec(v) and vec(B)`, force experienced is zero and the particle passes undeflected. For `theta = 90^(@)`, the particle moves along a circular arc and the magnetic force (qvB) provides the necessary centripetal force `(mv^(2)//r)`. For other values of `theta (theta !=0^(@), 180^(@), 90^(@))`, the charged particle moves along a helical path which is the resultant motion of simultaneous circular and translational motions.
Suppose a particle that carries a charge of magnitude q and has a mass `4 xx 10^(-15)` kg is moving in a region containing a uniform magnetic field `vec(B) = -0.4 hat(k) T`. At some instant, velocity of the particle is `vec(v) = (8 hat(i) - 6 hat(j) 4 hat(k)) xx 10^(6) m s^(-1)` and force acting on it has a magnitude 1.6 N
Angular frequency of rotation of particle, also called the `cyclotron frequency' is

A

Force acting on the dipole is zero

B

Force acting on the dipole is approximately `(PQ)/(4piepsilonr^(3))` and is acting upwards

C

Torque acting on the dipole is `(PQ)/(4pi epsilon_(0)r^(2))` in clockwise direction

D

Torque acting on the dipole is `(PQ)/(4pi epsilon_(0)r^(2))` in anti- clockwise direction

Text Solution

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The correct Answer is:
B, C
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