A cloud is at a potential of `8 xx 10^(6)` volt relative to the ground. A charge of 80 coulomd is transferred in lightening stroke betwee the cloud and the gorund. Assuming the potential of the cloud of remain constant, the energy dissipated is

Options

A. `6.4 xx 10^(8)` joule
B. `6.4 xx 10^(5)` joule
C. `10^(5)` joule
D. `10^(7)` joule

Answer

To solve the problem, we need to calculate the energy dissipated during a lightning stroke when a charge is transferred from the cloud to the ground. The energy dissipated can be calculated using the formula:

\[ \text{Energy} (E) = \text{Charge} (Q) \times \text{Potential} (V) \]

### Step-by-Step Solution:

1. **Identify the given values:**
- Potential of the cloud, \( V = 8 \times 10^6 \) volts
- Charge transferred, \( Q = 80 \) coulombs

2. **Use the formula for energy:**
\[ E = Q \times V \]

3. **Substitute the values into the formula:**
\[ E = 80 \, \text{C} \times 8 \times 10^6 \, \text{V} \]

4. **Calculate the energy:**
\[ E = 80 \times 8 \times 10^6 \]
\[ E = 640 \times 10^6 \, \text{J} \]

5. **Convert to standard scientific notation:**
\[ E = 6.4 \times 10^8 \, \text{J} \]

6. **Final Answer:**
The energy dissipated during the lightning stroke is:
\[ E = 6.4 \times 10^8 \, \text{J} \]