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Find the capacitance of a system of two ...

Find the capacitance of a system of two identical metal balls of radius . a . if the distance between their centres in equal to .b., with to `b gt gta` The system is located in a uniform dielectric with relative permittivity `epsilon`

A

`C=piepsilon_(0)epsilona`

B

`C=5piepsilon_(0)epsilona`

C

`C=2piepsilon_(0)epsilona`

D

`C=2piepsilon_(0)epsilon//a`

Text Solution

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The correct Answer is:
To find the capacitance of a system of two identical metal balls of radius \( a \) with the distance between their centers equal to \( b \) (where \( b \gg a \)), located in a uniform dielectric with relative permittivity \( \epsilon \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Configuration**: - We have two identical metal spheres (balls) each with radius \( a \). - The distance between their centers is \( b \), and it is given that \( b \gg a \). - The system is placed in a dielectric medium characterized by its relative permittivity \( \epsilon \). 2. **Capacitance of a Single Sphere**: - The capacitance \( C \) of a single isolated sphere in a medium with permittivity \( \epsilon \) is given by: \[ C = 4 \pi \epsilon_0 \epsilon a \] - Here, \( \epsilon_0 \) is the permittivity of free space. 3. **Capacitance of Each Sphere**: - For both spheres, since they are identical, the capacitance for each sphere is: \[ C_1 = C_2 = 4 \pi \epsilon_0 \epsilon a \] 4. **Combine the Capacitances**: - When two capacitors are in series, the total capacitance \( C_{\text{net}} \) can be calculated using the formula: \[ \frac{1}{C_{\text{net}}} = \frac{1}{C_1} + \frac{1}{C_2} \] - Substituting the values of \( C_1 \) and \( C_2 \): \[ \frac{1}{C_{\text{net}}} = \frac{1}{4 \pi \epsilon_0 \epsilon a} + \frac{1}{4 \pi \epsilon_0 \epsilon a} \] - This simplifies to: \[ \frac{1}{C_{\text{net}}} = \frac{2}{4 \pi \epsilon_0 \epsilon a} \] 5. **Calculate the Net Capacitance**: - Inverting the equation gives: \[ C_{\text{net}} = \frac{4 \pi \epsilon_0 \epsilon a}{2} = 2 \pi \epsilon_0 \epsilon a \] 6. **Final Result**: - Thus, the capacitance of the system of two identical metal balls is: \[ C_{\text{net}} = 2 \pi \epsilon_0 \epsilon a \] ### Conclusion: The capacitance of the system of two identical metal balls is given by: \[ C = 2 \pi \epsilon_0 \epsilon a \]
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