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Three long concentric conducting cylindr...

Three long concentric conducting cylindrical shells have radii R, 2R and `2sqrt2 R` Inner and outer shells are connected to each other. The capacitance across middle and inner shells per unit length is:

A

`(1/3in_0)/(ln2)`

B

`(6piin_0)/(ln2)`

C

`(piin_0)/(ln2)`

D

None

Text Solution

AI Generated Solution

The correct Answer is:
To find the capacitance across the middle and inner cylindrical shells per unit length, we can follow these steps: ### Step 1: Identify the Radii We have three concentric cylindrical shells with the following radii: - Inner shell (R1) = R - Middle shell (R2) = 2R - Outer shell (R3) = 2√2 R ### Step 2: Use the Capacitance Formula for Cylindrical Capacitors The capacitance \( C \) per unit length for a cylindrical capacitor is given by the formula: \[ C = \frac{2\pi \epsilon_0}{\ln\left(\frac{R_2}{R_1}\right)} \] where \( R_1 \) is the inner radius and \( R_2 \) is the outer radius. ### Step 3: Calculate Capacitance \( C_1 \) between Inner and Middle Shells For the capacitance \( C_1 \) between the inner shell (R) and the middle shell (2R): - \( R_1 = R \) - \( R_2 = 2R \) Substituting these values into the formula: \[ C_1 = \frac{2\pi \epsilon_0}{\ln\left(\frac{2R}{R}\right)} = \frac{2\pi \epsilon_0}{\ln(2)} \] ### Step 4: Calculate Capacitance \( C_2 \) between Middle and Outer Shells For the capacitance \( C_2 \) between the middle shell (2R) and the outer shell (2√2 R): - \( R_1 = 2R \) - \( R_2 = 2\sqrt{2}R \) Substituting these values into the formula: \[ C_2 = \frac{2\pi \epsilon_0}{\ln\left(\frac{2\sqrt{2}R}{2R}\right)} = \frac{2\pi \epsilon_0}{\ln\left(\sqrt{2}\right)} = \frac{2\pi \epsilon_0}{\frac{1}{2}\ln(2)} = \frac{4\pi \epsilon_0}{\ln(2)} \] ### Step 5: Combine the Capacitances Since the capacitors \( C_1 \) and \( C_2 \) are in parallel, the total capacitance \( C_{total} \) is given by: \[ C_{total} = C_1 + C_2 \] Substituting the values we calculated: \[ C_{total} = \frac{2\pi \epsilon_0}{\ln(2)} + \frac{4\pi \epsilon_0}{\ln(2)} = \frac{6\pi \epsilon_0}{\ln(2)} \] ### Final Answer Thus, the capacitance across the middle and inner shells per unit length is: \[ C_{total} = \frac{6\pi \epsilon_0}{\ln(2)} \] ---
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