Consider a capacitor as shown in figure. If we pull the plates of capacitor apart to a final position as shown in figure, then we must perform some work against the electric force. For this situation, mark out the correct statements.

Options

A. Work done is `(Q^2)/(2epsilon_(0)A)(d_(2)-d_(1))` and is stored in volume `A(d_(2)-d_(1))`
B. Work done is `+(Q^2)/(2epsilon_(0)A)(d_(2)-d_(1))` and is stored in volume `Ad_2`.
C. Work done is + `(epsilon_0AV^2)/(2)((d_2-d_1)/(d_1d_2))` and is stored in volume `A(d_2-d_1)`
D. Work done is + `(epsilon_0AV^2)/(2)((d_2-d_1)/(d_1d_2))` and is stored in volume `Ad_2`

Answer

C