A current of 4.8 A is flowing in a conductor the number of electrons passing per sec through the conductor will be

Options

A. `3xx10^(19)`
B. `7.68xx10^(20)`
C. `76.8xx10^(19)`
D. `3xx10^(20)`

Answer

To solve the problem of finding the number of electrons passing per second through a conductor with a current of 4.8 A, we can follow these steps:

### Step 1: Understand the relationship between current, charge, and time
The current (I) in a conductor is defined as the rate of flow of charge (Q) per unit time (t). Mathematically, this is expressed as:
\[ I = \frac{Q}{t} \]
Where:
- \( I \) is the current in amperes (A)
- \( Q \) is the charge in coulombs (C)
- \( t \) is the time in seconds (s)

### Step 2: Relate charge to the number of electrons
The total charge (Q) can also be expressed in terms of the number of electrons (n) and the charge of a single electron (e):
\[ Q = n \cdot e \]
Where:
- \( n \) is the number of electrons
- \( e \) is the charge of a single electron, approximately \( 1.6 \times 10^{-19} \) coulombs.

### Step 3: Rearrange the equation to find the number of electrons
We can combine the equations to find the number of electrons passing through the conductor:
\[ n = \frac{I \cdot t}{e} \]

### Step 4: Substitute the known values
Given:
- Current \( I = 4.8 \) A
- Time \( t = 1 \) s (since we want the number of electrons per second)
- Charge of an electron \( e = 1.6 \times 10^{-19} \) C

Substituting these values into the equation:
\[ n = \frac{4.8 \, \text{A} \cdot 1 \, \text{s}}{1.6 \times 10^{-19} \, \text{C}} \]

### Step 5: Calculate the number of electrons
Now, performing the calculation:
\[ n = \frac{4.8}{1.6 \times 10^{-19}} \]
\[ n = 3 \times 10^{19} \]

### Conclusion
Thus, the number of electrons passing through the conductor per second is:
\[ n = 3 \times 10^{19} \]

### Final Statement
Therefore, the answer is that \( 3 \times 10^{19} \) electrons are passing through the conductor per second.

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