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Passage-II: Consider a block conductin...

Passage-II:
Consider a block conducting material of resistivity .`rho`. shown in the figure. Current .I. enters at .A. and leaves from .D.. We apply superposition principle to find voltage .`DeltaV`. developed between .B. and .C.. The calculation is done in the following steps :
i) Take current .I. entering from .A. and assume it to spread over a hemispherical surface in the block.
ii) Calculate field E(r ) at distance .r. from A by using Ohm.s law `E= rhoj`, where j is the current per unit area at .r..
iii) From the .r. dependence of E(r ), obtain the potential V(r ) at r.
iv) Repeat (i), (ii), (iii) for current .I. leaving .D. and superpose results for .A. and .D..

For current entering at A the electric field at a distance .r. from A is

A

`(rhoI)/(8pi r^(2))`

B

`(rhoI)/(r^(2))`

C

`(rhoI)/(2pir^(2))`

D

`(rhoI)/(4pir^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
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