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Two cells of emf E(1) and E(2) are conne...

Two cells of emf `E_(1)` and `E_(2)` are connected to two resistors `R_(1) and R_(2)` as shown. If `E_(2)` is short circuited then current through `R_(1) and R_(2)` are

A

`(E_(1))/(E_(2)),0`

B

`0,(E_(1))/(R_(2))`

C

`(E_(1))/(R_(1)),0`

D

`0, (E_(1))/(R_(1))`

Text Solution

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The correct Answer is:
C
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AAKASH SERIES-CURRENT ELECTRICITY-PRACTICE SHEET (EXERCISE - III LEVEL-I (MAIN) (Straight Objective Type Questions))
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