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An ammeter has a resistance of 50Omega a...

An ammeter has a resistance of `50Omega` and a full scale deflection current `50muA`. It can be used as a voltmeter or as a higher range ammeter provided that a resistance is added to it. Which of the following is/are true?

A

10 V range with approximately `200kOmega` resistance in series

B

30 V range with approximately `200kOmega` resistance in series

C

1 mA range with `50Omega` resistance in parallel

D

0.1 mA range with `50Omega` resistance in parallel

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given information about the ammeter (or galvanometer) and determine its usage as a voltmeter and a higher range ammeter. ### Step-by-Step Solution: 1. **Identify Given Values**: - Resistance of the ammeter (R_g) = 50 Ω - Full scale deflection current (I_g) = 50 μA = 50 × 10^(-6) A 2. **Convert the Ammeter to a Voltmeter**: - When converting an ammeter to a voltmeter, we need to add a resistance (R) in series. - The total voltage (V) across the voltmeter can be calculated using Ohm's law: \[ V = I_g \times (R_g + R) \] - If we assume R = 200 kΩ = 200 × 10^3 Ω, then: \[ V = 50 \times 10^{-6} \times (50 + 200 \times 10^3) \] - Calculate: \[ V = 50 \times 10^{-6} \times (50 + 200000) = 50 \times 10^{-6} \times 200050 \] - Neglecting the 50 in comparison to 200000: \[ V \approx 50 \times 10^{-6} \times 200000 = 10 \text{ volts} \] 3. **Convert the Ammeter to a Higher Range Ammeter**: - To convert the ammeter to a higher range ammeter, we add a resistance (R_s) in parallel. - The total current (I) through the ammeter can be expressed as: \[ I = \frac{I_g \times (R_g + R_s)}{R_s} \] - Setting R_s = 50 Ω: \[ I = \frac{50 \times 10^{-6} \times (50 + 50)}{50} \] - Simplifying: \[ I = \frac{50 \times 10^{-6} \times 100}{50} = 100 \times 10^{-6} = 0.1 \text{ mA} \] 4. **Conclusion**: - The range of the voltmeter is approximately 10 volts. - The range of the higher range ammeter is 0.1 mA. ### Final Answers: - The statements regarding the voltmeter range being 10 volts and the ammeter range being 0.1 mA are true.
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