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The equation of a wave is y = 4 sin {pi/...

The equation of a wave is `y = 4 sin {pi/2(2t + x/8)}` where y , x are in cm and time in seconds. The phase difference between two position of the same particle which are occupied at time interval of 0.4 s is `x pi xx10^(-1)` , what is the value of x ?

A

The amplitude, wavelength, velocity and frequency of wave are 4cm, `16cm,32cm^(-1)` and 1Hz respectively with wave propagating along + x direction,

B

The amplitude, wavelength, velocity and frequency of wave are 4cm, 32cm, 16cm/s, and 0.5Hz respectively with wave propagating along -x direction

C

Two position occupied by the particle at time interval of 0.4s have a phase difference of `0.4 pi` radian

D

Two position occupied by the particle at separation of 12 cm have a phase difference of 135°

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B, C, D
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