The vibrations of a string of length 60 cm fixed at both ends are represented by the equation `y=4sin((pix)/15) cos (96 pi t)`, where x and y are in cm and t in seconds.
(a)What is the maximum displacement of a point at `x = 5cm`?
(b)Where are the nodes located along the string?
(c)What is the velocity of the particle at x=7.5cm and t=0.25s?
(d)Write down the equations of the component waves whose superposition gives the above wave.

Options

A. maximum displacement of a particle at a point at x = t cm is 4 cm
B. third node is formed at 30 cm from one end of the string
C. the velocity of a particle at x = 7.5 cm and t = 0.25 s is zero
D. equations of the component waves whose superposition gives the above equation are `y_(1) = 2sin((pix)/15 - 96pi)` and `y_(2) = 2sin((pix)/15 + 96 pi)`

Answer

B, C, D