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The distance between the tew slits in a ...

The distance between the tew slits in a Young's double slit experiment is d and the distance of the screen from the plane of the slits is b, P is a point on the screen directly infront of one of the slits. The path difference between the waves arriving at P from the two slits is

A

`(d^(2))/b`

B

`(d^(2))/(2b)`

C

`(2d^(2))/b`

D

`(d^(2))/(4b)`

Text Solution

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The correct Answer is:
B
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AAKASH SERIES-WAVE OPTICS-LECTURE SHEET EXERCISE-I (LEVEL -I) (MAIN) straight objective Type Questions
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