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The aperture of telescope is of 1m diame...

The aperture of telescope is of 1m diameter and wavelength of light incident on the on the paerture is `5500 A^(0)` . The angular limit if resolution of the telescope is

A

`6.71xx10^(-7)` radian

B

`3.35 xx10^(-7)` radians

C

`6.71 xx10^(-5)` radian

D

`3.35 xx10^(-5)` radians

Text Solution

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The correct Answer is:
To solve the problem, we need to find the angular limit of resolution of a telescope using the given parameters: the diameter of the aperture (D) and the wavelength of light (λ). ### Step-by-Step Solution: **Step 1: Identify the given values.** - Diameter of the aperture (D) = 1 m - Wavelength of light (λ) = 5500 Å (angstroms) **Step 2: Convert the wavelength from angstroms to meters.** 1 angstrom = \(10^{-10}\) meters, so: \[ \lambda = 5500 \, \text{Å} = 5500 \times 10^{-10} \, \text{m} = 5.5 \times 10^{-7} \, \text{m} \] **Step 3: Use the formula for the angular limit of resolution.** The formula for the angular limit of resolution (θ) is given by: \[ \theta = \frac{1.22 \lambda}{D} \] **Step 4: Substitute the values into the formula.** Substituting λ and D into the formula: \[ \theta = \frac{1.22 \times 5.5 \times 10^{-7}}{1} \] **Step 5: Calculate the value of θ.** Calculating the above expression: \[ \theta = 1.22 \times 5.5 \times 10^{-7} = 6.71 \times 10^{-7} \, \text{radians} \] **Step 6: State the final answer.** The angular limit of resolution of the telescope is: \[ \theta \approx 6.71 \times 10^{-7} \, \text{radians} \]
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