Home
Class 12
PHYSICS
In Young's double slit experiment the po...

In Young's double slit experiment the point source is placed slightly off the central axis as shown in figure. The plane of slits `(S_(1), S_(2))` and screen are separated by a distance of 2m. The separation between the slits is 10 mm. The position of the slit above the axis is 1mm. if the wavelength `lambda = 4000 Å` in the above arrangement

The thickness of the film in the above case is

A

`0.8` mm

B

`0.04` mm

C

`0.035` mm

D

`0.045` mm

Text Solution

Verified by Experts

The correct Answer is:
C
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WAVE OPTICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL - II ) LECTURE SHEET (ADVANCED ) (Matrix Matching Type Questions)|1 Videos
  • WAVE OPTICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL - II ) LECTURE SHEET (ADVANCED ) (Integer Type Quesiton)|3 Videos
  • WAVE OPTICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL - II ) LECTURE SHEET (ADVANCED ) (More Than one correct Type Questions)|4 Videos
  • WAVE MOTION AND SOUND

    AAKASH SERIES|Exercise PROBLEMS (LEVEL - II)|97 Videos
  • WAVES

    AAKASH SERIES|Exercise EXERCISE-III (Doppler effect :)|15 Videos

Similar Questions

Explore conceptually related problems

In Young's double-slit experiment, the point source is placed slightly off the central axis shown in Fig. 2.45. a. Find the nature and order of the interference at point P. b. Find the nature and order of the interference at point. O.

Young’s double slit experiment is performed with light of wavelength 550 nm . The separation between the slits is 1.10 mm and screen is placed at distance of 1 m . What is the distance between the consecutive bright or dark fringes

In YDSE, separation between slits is 0.15 mm, distance between slits and screen is 1.5 m and wavelength of light is 589 nm, then fringe width is

In YDSE, separation between slits is 0.15 mm, distance between slits and screen is 1.5 m and wavelength of light is 589 nm, then fringe width is

In a Young’s double slit experiment, the separation of the two slits is doubled. To keep the same spacing of fringes, the distance D of the screen from the slits should be made

In young's double slit experiment with monochromic light, fringes are obtained on a screen placed at some distance from the plane of slits. If the screen is moved by 5 cm towards the slits, then the change in fringe width is 30mum if the distance between the slits is 1mm, then calculate wavelength of the light used.

In the YDSE the monochronic source of wavelength lambda is palced at a distance d/2 from the central axis (as shown in the figure ) , where d is the separation between two slits S_(1) and S_(2) .Find the position of the central maxima . (Given d = 6 mm )

In a Young's double slit experiment the separation between the slits is 0.10 mm, the wavelength of light used is 600 mm and the interference pattern is observed on a screen 1.0 m away. Find the separation between the successive bright fringes.

In Young's double slit experiment slits are separated by 2 mm and the screen is placed at a distance of1.2 m from the slits. Light consisting of two wavelengths 6500Å and 5200Å are used to obtain interference fringes. The the separation between the fourth bright fringes the two wavelength is

In Young's double slit experiment, the separation between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is