If two deuterium nuclei get close enough to each other, the attraction of the strong nuclear force will fuse them to make an isotope of helium. This process releases a huge amount of energy. The range of nuclear force is `10^(-15)` m. This is the principle behind the nuclear fusion reactor. The deuterium nuclei moves to fast that, it is not possible to contain them by physical walls. Therefore they are confined magnetically (Assume coulomb law to hold even at `10^(-18)` m)
Two deuterium nuclei having same speed undergo a head on collision. Which of the following is closest to the minimum value of v (in km/sec) for which fusion occurs

Options

A. 122mT
B. 160M
C. 139mT
D. 212mT

Answer

C