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Nulei of radioactive element A are produ...

Nulei of radioactive element A are produced at any time t. the element A has decay constant `lambda`. Let N be number of nulei if element A at any time t. At time `t=t_0` dN/dt is minimum. Then the numbers of nuclei of element A at time `t=t_0` is

A

`K(ln2)/(lamda)+(3)/(2)((K-lamdaN_(0))/(lamda))`

B

`K(ln2)/(lamda)+(1)/(2)((K-lamdaN_(0))/(lamda))`

C

`K(ln2)/(lamda)-(1)/(2)((K-lamdaN_(0))/(lamda))`

D

`K(ln2)/(lamda)-2((K-lamdaN_(0))/(lamda))`

Text Solution

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The correct Answer is:
C
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