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The coefficient of viscosity of a liquid...

The coefficient of viscosity of a liquid of `sigma = 1.0 CGS` units as determined by measuring the terminal velocity of a spherical solid ball of density `p= 1.5 CGS` units inside the liquid. If the ball of radius 1.00cm attain terminal velocity 1cm/s, then the viscosity (in CGS units) of the liquid as calculated from the observations of the experimental is: [Take `g=10m//s^(2)` ]

A

`(100)/( 9)`

B

`(1000)/( 9)`

C

`(10)/( 9)`

D

`(1)/(9)`

Text Solution

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The correct Answer is:
To calculate the coefficient of viscosity (η) of the liquid using the given parameters, we can follow these steps: ### Step 1: Understand the formula for viscosity The coefficient of viscosity (η) can be calculated using the formula: \[ \eta = \frac{2}{9} \cdot r^2 \cdot \frac{(p - \sigma) \cdot g}{v} \] where: - \( r \) = radius of the ball - \( p \) = density of the ball - \( \sigma \) = density of the liquid - \( g \) = acceleration due to gravity - \( v \) = terminal velocity of the ball ### Step 2: Substitute the known values into the formula Given: - \( r = 1 \, \text{cm} \) - \( p = 1.5 \, \text{g/cm}^3 \) - \( \sigma = 1.0 \, \text{g/cm}^3 \) - \( g = 10 \, \text{m/s}^2 = 1000 \, \text{cm/s}^2 \) - \( v = 1 \, \text{cm/s} \) Now substituting these values into the formula: \[ \eta = \frac{2}{9} \cdot (1)^2 \cdot \frac{(1.5 - 1.0) \cdot 1000}{1} \] ### Step 3: Simplify the expression Calculating \( (1.5 - 1.0) \): \[ 1.5 - 1.0 = 0.5 \] Now substituting this back into the equation: \[ \eta = \frac{2}{9} \cdot 1 \cdot \frac{0.5 \cdot 1000}{1} \] This simplifies to: \[ \eta = \frac{2}{9} \cdot 0.5 \cdot 1000 \] ### Step 4: Calculate the final value Calculating \( 0.5 \cdot 1000 \): \[ 0.5 \cdot 1000 = 500 \] Now substituting this value: \[ \eta = \frac{2}{9} \cdot 500 \] Calculating \( \frac{2 \cdot 500}{9} \): \[ \eta = \frac{1000}{9} \] ### Step 5: Final result Thus, the coefficient of viscosity of the liquid is: \[ \eta = \frac{1000}{9} \, \text{CGS units} \] ### Summary The viscosity of the liquid, as calculated from the observations of the experiment, is \( \frac{1000}{9} \, \text{CGS units} \). ---
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